Bilinear Approximation to nth order Low Pass
Elliptic Filter.
Cuthbert Nyack
Frequency Response, Transfer function and pole locations are shown by
the applet below.
Fn = 0 shows the frequency response.
Fn = 1 shows the transfer function represented as a product of
quadratic factors.
Fn = 2 shows the pole and zero locations for the continuous Elliptic filter and the discrete Bilinear approximation.
To design a filter which has a gain of ~ -0.5dB at 0.12ws, ~ -85dB at
0.18ws and a passband ripple of 0.15dB, proceed as
follows:-
Set BL = 90, WL to 135 and R = 0.15 to locate the frequency markers
and set the pass band ripple.
Adjust N,
fc/fs until the conditions are met.
In this case N = 8,
fc/fs = 0.119 and
ws/wp = 1.639(ratio of stop band
frequency to pass band frequency).
The last entry in the first line of white text
shows the gain at 0.18ws as -88.46dB and the second line
shows the attenuation at 0.12ws is -0.421dB.
In this case, the minimum stop band
attenuation is 96.34dB.
Changing Fn to 1 shows the quadratic factors needed to realize the filter and Fn = 2 show the zeros and poles.
Return to main page
Return to page index
COPYRIGHT © 2008 Cuthbert Nyack.